Line slope calculator 4x+5y=50
Straight line given by points A[0; 10] and B[5; 6]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+10
Canonical form of the line equation: 4x+5y-50 = 0
Parametric form of the line equation:
x = 5t
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 12.5
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 7.8087
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [2.5; 8]
Perpendicular Bisector equation: 5x-4y+19.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (5; 6) ; |OB| = 7.8102
Scalar product OA .OB = 60
Angle ∠ AOB = 39°48'20″ = 0.6947 rad