Line slope calculator 4x+5y=50


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[5; 6]

Calculation:

Slope-intercept form of line: y = -0.8x+10

Canonical form of the line equation: 4x+5y-50 = 0

Parametric form of the line equation:
x = 5t
y = -4t+10      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 12.5

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 7.8087

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [2.5; 8]

Perpendicular Bisector equation: 5x-4y+19.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (5; 6) ;   |OB| = 7.8102
Scalar product OA .OB = 60
Angle ∠ AOB = 39°48'20″ = 0.6947 rad