Line slope calculator 5x+6y=60


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[6; 5]

Calculation:

Slope-intercept form of line: y = -0.8333x+10

Canonical form of the line equation: 5x+6y-60 = 0

Parametric form of the line equation:
x = 6t
y = -5t+10      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 12

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 7.6822

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [3; 7.5]

Perpendicular Bisector equation: 6x-5y+19.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 50
Angle ∠ AOB = 50°11'40″ = 0.8761 rad