Line slope calculator 5x+6y=60
Straight line given by points A[0; 10] and B[6; 5]
Calculation:
Slope: m = -0.8333Slope-intercept form of line: y = -0.8333x+10
Canonical form of the line equation: 5x+6y-60 = 0
Parametric form of the line equation:
x = 6t
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -39°48'20″ = -0.6947 rad
X intercept: x0 = 12
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 7.6822
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; -5)
Normal vector: n = (5; 6)
Midpoint of the segment AB: M = [3; 7.5]
Perpendicular Bisector equation: 6x-5y+19.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 50
Angle ∠ AOB = 50°11'40″ = 0.8761 rad