Line slope calculator 7x+8y=80
Straight line given by points A[0; 10] and B[8; 3]
Calculation:
Slope: m = -0.875Slope-intercept form of line: y = -0.875x+10
Canonical form of the line equation: 7x+8y-80 = 0
Parametric form of the line equation:
x = 8t
y = -7t+10 ; t ∈ R
Slope angle of line: φ = -41°11'9″ = -0.7188 rad
X intercept: x0 = 11.4286
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 7.5258
The length of the segment AB: |AB| = 10.6301
Vector: AB = (8; -7)
Normal vector: n = (7; 8)
Midpoint of the segment AB: M = [4; 6.5]
Perpendicular Bisector equation: 8x-7y+13.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 30
Angle ∠ AOB = 69°26'38″ = 1.212 rad