Line slope calculator 7x+8y=80


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -0.875x+10

Canonical form of the line equation: 7x+8y-80 = 0

Parametric form of the line equation:
x = 8t
y = -7t+10      ; t ∈ R

Slope: m = -0.875

Slope angle of line: φ = -41°11'9″ = -0.7188 rad

X intercept: x0 = 11.4286

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 7.5258

The length of the segment AB: |AB| = 10.6301

Vector: AB = (8; -7)

Normal vector: n = (7; 8)

Midpoint of the segment AB: M = [4; 6.5]

Perpendicular Bisector equation: 8x-7y+13.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 30
Angle ∠ AOB = 69°26'38″ = 1.212 rad