Line slope calculator 6x+8y=80


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[8; 4]

Calculation:

Slope-intercept form of line: y = -0.75x+10

Canonical form of the line equation: 6x+8y-80 = 0

Parametric form of the line equation:
x = 8t
y = -6t+10      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 13.3333

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 8

The length of the segment AB: |AB| = 10

Vector: AB = (8; -6)

Normal vector: n = (6; 8)

Midpoint of the segment AB: M = [4; 7]

Perpendicular Bisector equation: 8x-6y+10 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (8; 4) ;   |OB| = 8.9443
Scalar product OA .OB = 40
Angle ∠ AOB = 63°26'6″ = 1.1071 rad