Line slope calculator 5x+8y=80


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[8; 5]

Calculation:

Slope-intercept form of line: y = -0.625x+10

Canonical form of the line equation: 5x+8y-80 = 0

Parametric form of the line equation:
x = 8t
y = -5t+10      ; t ∈ R

Slope: m = -0.625

Slope angle of line: φ = -32°19″ = -0.5586 rad

X intercept: x0 = 16

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 8.48

The length of the segment AB: |AB| = 9.434

Vector: AB = (8; -5)

Normal vector: n = (5; 8)

Midpoint of the segment AB: M = [4; 7.5]

Perpendicular Bisector equation: 8x-5y+5.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (8; 5) ;   |OB| = 9.434
Scalar product OA .OB = 50
Angle ∠ AOB = 57°59'41″ = 1.0122 rad