Line slope calculator 2x+8y=80


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[8; 8]

Calculation:

Slope-intercept form of line: y = -0.25x+10

Canonical form of the line equation: 2x+8y-80 = 0

Parametric form of the line equation:
x = 8t
y = -2t+10      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 40

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 9.7014

The length of the segment AB: |AB| = 8.2462

Vector: AB = (8; -2)

Normal vector: n = (2; 8)

Midpoint of the segment AB: M = [4; 9]

Perpendicular Bisector equation: 8x-2y-14 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 80
Angle ∠ AOB = 45° = 0.7854 rad