Line slope calculator 10x+9y=90
Straight line given by points A[0; 10] and B[9; 0]
Calculation:
Slope: m = -1.1111Slope-intercept form of line: y = -1.1111x+10
Canonical form of the line equation: 10x+9y-90 = 0
Parametric form of the line equation:
x = 9t
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -48°46″ = -0.838 rad
X intercept: x0 = 9
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 6.6896
The length of the segment AB: |AB| = 13.4536
Vector: AB = (9; -10)
Normal vector: n = (10; 9)
Midpoint of the segment AB: M = [4.5; 5]
Perpendicular Bisector equation: 9x-10y+9.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad