Line slope calculator 10x+9y=90


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -1.1111x+10

Canonical form of the line equation: 10x+9y-90 = 0

Parametric form of the line equation:
x = 9t
y = -10t+10      ; t ∈ R

Slope: m = -1.1111

Slope angle of line: φ = -48°46″ = -0.838 rad

X intercept: x0 = 9

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 6.6896

The length of the segment AB: |AB| = 13.4536

Vector: AB = (9; -10)

Normal vector: n = (10; 9)

Midpoint of the segment AB: M = [4.5; 5]

Perpendicular Bisector equation: 9x-10y+9.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad