Line slope calculator 8x+9y=90
Straight line given by points A[0; 10] and B[9; 2]
Calculation:
Slope: m = -0.8889Slope-intercept form of line: y = -0.8889x+10
Canonical form of the line equation: 8x+9y-90 = 0
Parametric form of the line equation:
x = 9t
y = -8t+10 ; t ∈ R
Slope angle of line: φ = -41°38'1″ = -0.7266 rad
X intercept: x0 = 11.25
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 7.4741
The length of the segment AB: |AB| = 12.0416
Vector: AB = (9; -8)
Normal vector: n = (8; 9)
Midpoint of the segment AB: M = [4.5; 6]
Perpendicular Bisector equation: 9x-8y+7.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (9; 2) ; |OB| = 9.2195
Scalar product OA .OB = 20
Angle ∠ AOB = 77°28'16″ = 1.3521 rad