Line slope calculator x+4y=8
Straight line given by points A[0; 2] and B[4; 1]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+2
Canonical form of the line equation: x+4y-8 = 0
Parametric form of the line equation:
x = 4t
y = -t+2 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 8
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.9403
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [2; 1.5]
Perpendicular Bisector equation: 4x-y-6.5 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (4; 1) ; |OB| = 4.1231
Scalar product OA .OB = 2
Angle ∠ AOB = 75°57'50″ = 1.3258 rad