Line slope calculator x+4y=8


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[4; 1]

Calculation:

Slope-intercept form of line: y = -0.25x+2

Canonical form of the line equation: x+4y-8 = 0

Parametric form of the line equation:
x = 4t
y = -t+2      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 8

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.9403

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [2; 1.5]

Perpendicular Bisector equation: 4x-y-6.5 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 2
Angle ∠ AOB = 75°57'50″ = 1.3258 rad