Line slope calculator 2x+5y=10
Straight line given by points A[0; 2] and B[5; 0]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+2
Canonical form of the line equation: 2x+5y-10 = 0
Parametric form of the line equation:
x = 5t
y = -2t+2 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 5
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.857
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [2.5; 1]
Perpendicular Bisector equation: 5x-2y-10.5 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad