Line slope calculator x+5y=10
Straight line given by points A[0; 2] and B[5; 1]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+2
Canonical form of the line equation: x+5y-10 = 0
Parametric form of the line equation:
x = 5t
y = -t+2 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 10
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.9612
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [2.5; 1.5]
Perpendicular Bisector equation: 5x-y-11 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 2
Angle ∠ AOB = 78°41'24″ = 1.3734 rad