Line slope calculator 8x-5y=-10


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[5; 10]

Calculation:

Slope-intercept form of line: y = 1.6x+2

Canonical form of the line equation: 8x-5y+10 = 0

Parametric form of the line equation:
x = 5t
y = 8t+2      ; t ∈ R

Slope: m = 1.6

Slope angle of line: φ = 57°59'41″ = 1.0122 rad

X intercept: x0 = -1.25

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.06

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; 8)

Normal vector: n = (8; -5)

Midpoint of the segment AB: M = [2.5; 6]

Perpendicular Bisector equation: 5x+8y-60.5 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (5; 10) ;   |OB| = 11.1803
Scalar product OA .OB = 20
Angle ∠ AOB = 26°33'54″ = 0.4636 rad