Line slope calculator 4x-5y=-10
Straight line given by points A[0; 2] and B[5; 6]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+2
Canonical form of the line equation: 4x-5y+10 = 0
Parametric form of the line equation:
x = 5t
y = 4t+2 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -2.5
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.5617
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [2.5; 4]
Perpendicular Bisector equation: 5x+4y-28.5 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (5; 6) ; |OB| = 7.8102
Scalar product OA .OB = 12
Angle ∠ AOB = 39°48'20″ = 0.6947 rad