Line slope calculator x+6y=12


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -0.1667x+2

Canonical form of the line equation: x+6y-12 = 0

Parametric form of the line equation:
x = 6t
y = -t+2      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 12

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.9728

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [3; 1.5]

Perpendicular Bisector equation: 6x-y-16.5 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 2
Angle ∠ AOB = 80°32'16″ = 1.4056 rad