Line slope calculator x+8y=16


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[0; 2] and B[8; 1]

Calculation:

Slope: m = -0.125

Slope-intercept form of line: y = -0.125x+2

Canonical form of the line equation: x+8y-16 = 0

Parametric form of the line equation:
x = 8t
y = -t+2      ; t ∈ R

Slope angle of line: φ = -7°7'30″ = -0.1244 rad

X intercept: x0 = 16

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.9846

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; -1)

Normal vector: n = (1; 8)

Midpoint of the segment AB: M = [4; 1.5]

Perpendicular Bisector equation: 8x-y-30.5 = 0

Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 2
Angle ∠ AOB = 82°52'30″ = 1.4464 rad