Line slope calculator x-8y=-16


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[8; 3]

Calculation:

Slope-intercept form of line: y = 0.125x+2

Canonical form of the line equation: x-8y+16 = 0

Parametric form of the line equation:
x = 8t
y = t+2      ; t ∈ R

Slope: m = 0.125

Slope angle of line: φ = 7°7'30″ = 0.1244 rad

X intercept: x0 = -16

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.9846

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; 1)

Normal vector: n = (1; -8)

Midpoint of the segment AB: M = [4; 2.5]

Perpendicular Bisector equation: 8x+y-34.5 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 6
Angle ∠ AOB = 69°26'38″ = 1.212 rad