Line slope calculator 3x-8y=-16


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[8; 5]

Calculation:

Slope-intercept form of line: y = 0.375x+2

Canonical form of the line equation: 3x-8y+16 = 0

Parametric form of the line equation:
x = 8t
y = 3t+2      ; t ∈ R

Slope: m = 0.375

Slope angle of line: φ = 20°33'22″ = 0.3588 rad

X intercept: x0 = -5.3333

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.8727

The length of the segment AB: |AB| = 8.544

Vector: AB = (8; 3)

Normal vector: n = (3; -8)

Midpoint of the segment AB: M = [4; 3.5]

Perpendicular Bisector equation: 8x+3y-42.5 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (8; 5) ;   |OB| = 9.434
Scalar product OA .OB = 10
Angle ∠ AOB = 57°59'41″ = 1.0122 rad