Line slope calculator 2x+9y=18
Straight line given by points A[0; 2] and B[9; 0]
Calculation:
Slope: m = -0.2222Slope-intercept form of line: y = -0.2222x+2
Canonical form of the line equation: 2x+9y-18 = 0
Parametric form of the line equation:
x = 9t
y = -2t+2 ; t ∈ R
Slope angle of line: φ = -12°31'44″ = -0.2187 rad
X intercept: x0 = 9
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.9524
The length of the segment AB: |AB| = 9.2195
Vector: AB = (9; -2)
Normal vector: n = (2; 9)
Midpoint of the segment AB: M = [4.5; 1]
Perpendicular Bisector equation: 9x-2y-38.5 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad