Line slope calculator x+9y=18
Straight line given by points A[0; 2] and B[9; 1]
Calculation:
Slope: m = -0.1111Slope-intercept form of line: y = -0.1111x+2
Canonical form of the line equation: x+9y-18 = 0
Parametric form of the line equation:
x = 9t
y = -t+2 ; t ∈ R
Slope angle of line: φ = -6°20'25″ = -0.1107 rad
X intercept: x0 = 18
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.9878
The length of the segment AB: |AB| = 9.0554
Vector: AB = (9; -1)
Normal vector: n = (1; 9)
Midpoint of the segment AB: M = [4.5; 1.5]
Perpendicular Bisector equation: 9x-y-39 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 2
Angle ∠ AOB = 83°39'35″ = 1.4601 rad