Line slope calculator x+9y=18


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[9; 1]

Calculation:

Slope-intercept form of line: y = -0.1111x+2

Canonical form of the line equation: x+9y-18 = 0

Parametric form of the line equation:
x = 9t
y = -t+2      ; t ∈ R

Slope: m = -0.1111

Slope angle of line: φ = -6°20'25″ = -0.1107 rad

X intercept: x0 = 18

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.9878

The length of the segment AB: |AB| = 9.0554

Vector: AB = (9; -1)

Normal vector: n = (1; 9)

Midpoint of the segment AB: M = [4.5; 1.5]

Perpendicular Bisector equation: 9x-y-39 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (9; 1) ;   |OB| = 9.0554
Scalar product OA .OB = 2
Angle ∠ AOB = 83°39'35″ = 1.4601 rad