Line slope calculator x-9y=-18


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[9; 3]

Calculation:

Slope-intercept form of line: y = 0.1111x+2

Canonical form of the line equation: x-9y+18 = 0

Parametric form of the line equation:
x = 9t
y = t+2      ; t ∈ R

Slope: m = 0.1111

Slope angle of line: φ = 6°20'25″ = 0.1107 rad

X intercept: x0 = -18

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.9878

The length of the segment AB: |AB| = 9.0554

Vector: AB = (9; 1)

Normal vector: n = (1; -9)

Midpoint of the segment AB: M = [4.5; 2.5]

Perpendicular Bisector equation: 9x+y-43 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (9; 3) ;   |OB| = 9.4868
Scalar product OA .OB = 6
Angle ∠ AOB = 71°33'54″ = 1.249 rad