Line slope calculator x-9y=-18
Straight line given by points A[0; 2] and B[9; 3]
Calculation:
Slope: m = 0.1111Slope-intercept form of line: y = 0.1111x+2
Canonical form of the line equation: x-9y+18 = 0
Parametric form of the line equation:
x = 9t
y = t+2 ; t ∈ R
Slope angle of line: φ = 6°20'25″ = 0.1107 rad
X intercept: x0 = -18
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.9878
The length of the segment AB: |AB| = 9.0554
Vector: AB = (9; 1)
Normal vector: n = (1; -9)
Midpoint of the segment AB: M = [4.5; 2.5]
Perpendicular Bisector equation: 9x+y-43 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (9; 3) ; |OB| = 9.4868
Scalar product OA .OB = 6
Angle ∠ AOB = 71°33'54″ = 1.249 rad