Line slope calculator 4x-9y=-18
Straight line given by points A[0; 2] and B[9; 6]
Calculation:
Slope: m = 0.4444Slope-intercept form of line: y = 0.4444x+2
Canonical form of the line equation: 4x-9y+18 = 0
Parametric form of the line equation:
x = 9t
y = 4t+2 ; t ∈ R
Slope angle of line: φ = 23°57'45″ = 0.4182 rad
X intercept: x0 = -4.5
Y intercept: y0 = q = 2
Distance line from the origin: d0 = 1.8276
The length of the segment AB: |AB| = 9.8489
Vector: AB = (9; 4)
Normal vector: n = (4; -9)
Midpoint of the segment AB: M = [4.5; 4]
Perpendicular Bisector equation: 9x+4y-56.5 = 0
Vector OA = (0; 2) ; |OA| = 2
Vector OB = (9; 6) ; |OB| = 10.8167
Scalar product OA .OB = 12
Angle ∠ AOB = 56°18'36″ = 0.9828 rad