Line slope calculator 3x+y=3
Straight line given by points A[0; 3] and B[1; 0]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+3
Canonical form of the line equation: 3x+y-3 = 0
Parametric form of the line equation:
x = t
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 1
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 0.9487
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [0.5; 1.5]
Perpendicular Bisector equation: x-3y+4 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (1; 0) ; |OB| = 1
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad