Line slope calculator 3x+10y=30
Straight line given by points A[0; 3] and B[10; 0]
Calculation:
Slope: m = -0.3Slope-intercept form of line: y = -0.3x+3
Canonical form of the line equation: 3x+10y-30 = 0
Parametric form of the line equation:
x = 10t
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -16°41'57″ = -0.2915 rad
X intercept: x0 = 10
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.8735
The length of the segment AB: |AB| = 10.4403
Vector: AB = (10; -3)
Normal vector: n = (3; 10)
Midpoint of the segment AB: M = [5; 1.5]
Perpendicular Bisector equation: 10x-3y-45.5 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad