Line slope calculator 3x+10y=30


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[0; 3] and B[10; 0]

Calculation:

Slope: m = -0.3

Slope-intercept form of line: y = -0.3x+3

Canonical form of the line equation: 3x+10y-30 = 0

Parametric form of the line equation:
x = 10t
y = -3t+3      ; t ∈ R

Slope angle of line: φ = -16°41'57″ = -0.2915 rad

X intercept: x0 = 10

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.8735

The length of the segment AB: |AB| = 10.4403

Vector: AB = (10; -3)

Normal vector: n = (3; 10)

Midpoint of the segment AB: M = [5; 1.5]

Perpendicular Bisector equation: 10x-3y-45.5 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad