Line slope calculator x+3y=9


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[3; 2]

Calculation:

Slope-intercept form of line: y = -0.3333x+3

Canonical form of the line equation: x+3y-9 = 0

Parametric form of the line equation:
x = 3t
y = -t+3      ; t ∈ R

Slope: m = -0.3333

Slope angle of line: φ = -18°26'6″ = -0.3218 rad

X intercept: x0 = 9

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.846

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; -1)

Normal vector: n = (1; 3)

Midpoint of the segment AB: M = [1.5; 2.5]

Perpendicular Bisector equation: 3x-y-2 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (3; 2) ;   |OB| = 3.6056
Scalar product OA .OB = 6
Angle ∠ AOB = 56°18'36″ = 0.9828 rad