Line slope calculator x-3y=-9


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[3; 4]

Calculation:

Slope-intercept form of line: y = 0.3333x+3

Canonical form of the line equation: x-3y+9 = 0

Parametric form of the line equation:
x = 3t
y = t+3      ; t ∈ R

Slope: m = 0.3333

Slope angle of line: φ = 18°26'6″ = 0.3218 rad

X intercept: x0 = -9

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.846

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; 1)

Normal vector: n = (1; -3)

Midpoint of the segment AB: M = [1.5; 3.5]

Perpendicular Bisector equation: 3x+y-8 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (3; 4) ;   |OB| = 5
Scalar product OA .OB = 12
Angle ∠ AOB = 36°52'12″ = 0.6435 rad