Line slope calculator 2x-3y=-9
Straight line given by points A[0; 3] and B[3; 5]
Calculation:
Slope: m = 0.6667Slope-intercept form of line: y = 0.6667x+3
Canonical form of the line equation: 2x-3y+9 = 0
Parametric form of the line equation:
x = 3t
y = 2t+3 ; t ∈ R
Slope angle of line: φ = 33°41'24″ = 0.588 rad
X intercept: x0 = -4.5
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.4962
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; 2)
Normal vector: n = (2; -3)
Midpoint of the segment AB: M = [1.5; 4]
Perpendicular Bisector equation: 3x+2y-12.5 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (3; 5) ; |OB| = 5.831
Scalar product OA .OB = 15
Angle ∠ AOB = 30°57'50″ = 0.5404 rad