Line slope calculator x-4y=-12
Straight line given by points A[0; 3] and B[4; 4]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+3
Canonical form of the line equation: x-4y+12 = 0
Parametric form of the line equation:
x = 4t
y = t+3 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -12
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.9104
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [2; 3.5]
Perpendicular Bisector equation: 4x+y-11.5 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (4; 4) ; |OB| = 5.6569
Scalar product OA .OB = 12
Angle ∠ AOB = 45° = 0.7854 rad