Line slope calculator x-4y=-12


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[4; 4]

Calculation:

Slope-intercept form of line: y = 0.25x+3

Canonical form of the line equation: x-4y+12 = 0

Parametric form of the line equation:
x = 4t
y = t+3      ; t ∈ R

Slope: m = 0.25

Slope angle of line: φ = 14°2'10″ = 0.245 rad

X intercept: x0 = -12

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.9104

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; 1)

Normal vector: n = (1; -4)

Midpoint of the segment AB: M = [2; 3.5]

Perpendicular Bisector equation: 4x+y-11.5 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (4; 4) ;   |OB| = 5.6569
Scalar product OA .OB = 12
Angle ∠ AOB = 45° = 0.7854 rad