Line slope calculator 5x-4y=-12


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[4; 8]

Calculation:

Slope-intercept form of line: y = 1.25x+3

Canonical form of the line equation: 5x-4y+12 = 0

Parametric form of the line equation:
x = 4t
y = 5t+3      ; t ∈ R

Slope: m = 1.25

Slope angle of line: φ = 51°20'25″ = 0.8961 rad

X intercept: x0 = -2.4

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 1.8741

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; 5)

Normal vector: n = (5; -4)

Midpoint of the segment AB: M = [2; 5.5]

Perpendicular Bisector equation: 4x+5y-35.5 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (4; 8) ;   |OB| = 8.9443
Scalar product OA .OB = 24
Angle ∠ AOB = 26°33'54″ = 0.4636 rad