Line slope calculator 2x+5y=15


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -0.4x+3

Canonical form of the line equation: 2x+5y-15 = 0

Parametric form of the line equation:
x = 5t
y = -2t+3      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 7.5

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.7854

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [2.5; 2]

Perpendicular Bisector equation: 5x-2y-8.5 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 3
Angle ∠ AOB = 78°41'24″ = 1.3734 rad