Line slope calculator x+5y=15
Straight line given by points A[0; 3] and B[5; 2]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+3
Canonical form of the line equation: x+5y-15 = 0
Parametric form of the line equation:
x = 5t
y = -t+3 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 15
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.9417
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [2.5; 2.5]
Perpendicular Bisector equation: 5x-y-10 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (5; 2) ; |OB| = 5.3852
Scalar product OA .OB = 6
Angle ∠ AOB = 68°11'55″ = 1.1903 rad