Line slope calculator 2x-5y=-15
Straight line given by points A[0; 3] and B[5; 5]
Calculation:
Slope: m = 0.4Slope-intercept form of line: y = 0.4x+3
Canonical form of the line equation: 2x-5y+15 = 0
Parametric form of the line equation:
x = 5t
y = 2t+3 ; t ∈ R
Slope angle of line: φ = 21°48'5″ = 0.3805 rad
X intercept: x0 = -7.5
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.7854
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; 2)
Normal vector: n = (2; -5)
Midpoint of the segment AB: M = [2.5; 4]
Perpendicular Bisector equation: 5x+2y-20.5 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 15
Angle ∠ AOB = 45° = 0.7854 rad