Line slope calculator 3x-5y=-15


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[5; 6]

Calculation:

Slope-intercept form of line: y = 0.6x+3

Canonical form of the line equation: 3x-5y+15 = 0

Parametric form of the line equation:
x = 5t
y = 3t+3      ; t ∈ R

Slope: m = 0.6

Slope angle of line: φ = 30°57'50″ = 0.5404 rad

X intercept: x0 = -5

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.5725

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; 3)

Normal vector: n = (3; -5)

Midpoint of the segment AB: M = [2.5; 4.5]

Perpendicular Bisector equation: 5x+3y-26 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (5; 6) ;   |OB| = 7.8102
Scalar product OA .OB = 18
Angle ∠ AOB = 39°48'20″ = 0.6947 rad