Line slope calculator x+6y=18


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[6; 2]

Calculation:

Slope-intercept form of line: y = -0.1667x+3

Canonical form of the line equation: x+6y-18 = 0

Parametric form of the line equation:
x = 6t
y = -t+3      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 18

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.9592

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [3; 2.5]

Perpendicular Bisector equation: 6x-y-15.5 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (6; 2) ;   |OB| = 6.3246
Scalar product OA .OB = 6
Angle ∠ AOB = 71°33'54″ = 1.249 rad