Line slope calculator 6x-10y=-40
Straight line given by points A[0; 4] and B[10; 10]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x+4
Canonical form of the line equation: 6x-10y+40 = 0
Parametric form of the line equation:
x = 10t
y = 6t+4 ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = -6.6667
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.43
The length of the segment AB: |AB| = 11.6619
Vector: AB = (10; 6)
Normal vector: n = (6; -10)
Midpoint of the segment AB: M = [5; 7]
Perpendicular Bisector equation: 10x+6y-92 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (10; 10) ; |OB| = 14.1421
Scalar product OA .OB = 40
Angle ∠ AOB = 45° = 0.7854 rad