Line slope calculator 6x-10y=-40


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[10; 10]

Calculation:

Slope-intercept form of line: y = 0.6x+4

Canonical form of the line equation: 6x-10y+40 = 0

Parametric form of the line equation:
x = 10t
y = 6t+4      ; t ∈ R

Slope: m = 0.6

Slope angle of line: φ = 30°57'50″ = 0.5404 rad

X intercept: x0 = -6.6667

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.43

The length of the segment AB: |AB| = 11.6619

Vector: AB = (10; 6)

Normal vector: n = (6; -10)

Midpoint of the segment AB: M = [5; 7]

Perpendicular Bisector equation: 10x+6y-92 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (10; 10) ;   |OB| = 14.1421
Scalar product OA .OB = 40
Angle ∠ AOB = 45° = 0.7854 rad