Line slope calculator x+10y=40
Straight line given by points A[0; 4] and B[10; 3]
Calculation:
Slope: m = -0.1Slope-intercept form of line: y = -0.1x+4
Canonical form of the line equation: x+10y-40 = 0
Parametric form of the line equation:
x = 10t
y = -t+4 ; t ∈ R
Slope angle of line: φ = -5°42'38″ = -0.0997 rad
X intercept: x0 = 40
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.9801
The length of the segment AB: |AB| = 10.0499
Vector: AB = (10; -1)
Normal vector: n = (1; 10)
Midpoint of the segment AB: M = [5; 3.5]
Perpendicular Bisector equation: 10x-y-46.5 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 12
Angle ∠ AOB = 73°18'3″ = 1.2793 rad