Line slope calculator x+10y=40


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -0.1x+4

Canonical form of the line equation: x+10y-40 = 0

Parametric form of the line equation:
x = 10t
y = -t+4      ; t ∈ R

Slope: m = -0.1

Slope angle of line: φ = -5°42'38″ = -0.0997 rad

X intercept: x0 = 40

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.9801

The length of the segment AB: |AB| = 10.0499

Vector: AB = (10; -1)

Normal vector: n = (1; 10)

Midpoint of the segment AB: M = [5; 3.5]

Perpendicular Bisector equation: 10x-y-46.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 12
Angle ∠ AOB = 73°18'3″ = 1.2793 rad