Line slope calculator 3x+2y=8


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[2; 1]

Calculation:

Slope-intercept form of line: y = -1.5x+4

Canonical form of the line equation: 3x+2y-8 = 0

Parametric form of the line equation:
x = 2t
y = -3t+4      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 2.6667

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 2.2188

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; -3)

Normal vector: n = (3; 2)

Midpoint of the segment AB: M = [1; 2.5]

Perpendicular Bisector equation: 2x-3y+5.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (2; 1) ;   |OB| = 2.2361
Scalar product OA .OB = 4
Angle ∠ AOB = 63°26'6″ = 1.1071 rad