Line slope calculator 2x+3y=12
Straight line given by points A[0; 4] and B[3; 2]
Calculation:
Slope: m = -0.6667Slope-intercept form of line: y = -0.6667x+4
Canonical form of the line equation: 2x+3y-12 = 0
Parametric form of the line equation:
x = 3t
y = -2t+4 ; t ∈ R
Slope angle of line: φ = -33°41'24″ = -0.588 rad
X intercept: x0 = 6
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.3282
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; -2)
Normal vector: n = (2; 3)
Midpoint of the segment AB: M = [1.5; 3]
Perpendicular Bisector equation: 3x-2y+1.5 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (3; 2) ; |OB| = 3.6056
Scalar product OA .OB = 8
Angle ∠ AOB = 56°18'36″ = 0.9828 rad