Line slope calculator 2x-3y=-12


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[3; 6]

Calculation:

Slope-intercept form of line: y = 0.6667x+4

Canonical form of the line equation: 2x-3y+12 = 0

Parametric form of the line equation:
x = 3t
y = 2t+4      ; t ∈ R

Slope: m = 0.6667

Slope angle of line: φ = 33°41'24″ = 0.588 rad

X intercept: x0 = -6

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.3282

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; 2)

Normal vector: n = (2; -3)

Midpoint of the segment AB: M = [1.5; 5]

Perpendicular Bisector equation: 3x+2y-14.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (3; 6) ;   |OB| = 6.7082
Scalar product OA .OB = 24
Angle ∠ AOB = 26°33'54″ = 0.4636 rad