Line slope calculator 3x+4y=16


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[4; 1]

Calculation:

Slope-intercept form of line: y = -0.75x+4

Canonical form of the line equation: 3x+4y-16 = 0

Parametric form of the line equation:
x = 4t
y = -3t+4      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 5.3333

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.2

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [2; 2.5]

Perpendicular Bisector equation: 4x-3y-0.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 4
Angle ∠ AOB = 75°57'50″ = 1.3258 rad