Line slope calculator x+4y=16


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[4; 3]

Calculation:

Slope-intercept form of line: y = -0.25x+4

Canonical form of the line equation: x+4y-16 = 0

Parametric form of the line equation:
x = 4t
y = -t+4      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 16

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.8806

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [2; 3.5]

Perpendicular Bisector equation: 4x-y-4.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 12
Angle ∠ AOB = 53°7'48″ = 0.9273 rad