Line slope calculator 4x+5y=20
Straight line given by points A[0; 4] and B[5; 0]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+4
Canonical form of the line equation: 4x+5y-20 = 0
Parametric form of the line equation:
x = 5t
y = -4t+4 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 5
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.1235
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [2.5; 2]
Perpendicular Bisector equation: 5x-4y-4.5 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad