Line slope calculator 3x+5y=20
Straight line given by points A[0; 4] and B[5; 1]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+4
Canonical form of the line equation: 3x+5y-20 = 0
Parametric form of the line equation:
x = 5t
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 6.6667
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.43
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [2.5; 2.5]
Perpendicular Bisector equation: 5x-3y-5 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 4
Angle ∠ AOB = 78°41'24″ = 1.3734 rad