Line slope calculator 3x+5y=20


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -0.6x+4

Canonical form of the line equation: 3x+5y-20 = 0

Parametric form of the line equation:
x = 5t
y = -3t+4      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 6.6667

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.43

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [2.5; 2.5]

Perpendicular Bisector equation: 5x-3y-5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 4
Angle ∠ AOB = 78°41'24″ = 1.3734 rad