Line slope calculator x+5y=20


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[5; 3]

Calculation:

Slope-intercept form of line: y = -0.2x+4

Canonical form of the line equation: x+5y-20 = 0

Parametric form of the line equation:
x = 5t
y = -t+4      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 20

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.9223

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [2.5; 3.5]

Perpendicular Bisector equation: 5x-y-9 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (5; 3) ;   |OB| = 5.831
Scalar product OA .OB = 12
Angle ∠ AOB = 59°2'10″ = 1.0304 rad