Line slope calculator x-5y=-20
Straight line given by points A[0; 4] and B[5; 5]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x+4
Canonical form of the line equation: x-5y+20 = 0
Parametric form of the line equation:
x = 5t
y = t+4 ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = -20
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.9223
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [2.5; 4.5]
Perpendicular Bisector equation: 5x+y-17 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 20
Angle ∠ AOB = 45° = 0.7854 rad