Line slope calculator 4x-5y=-20
Straight line given by points A[0; 4] and B[5; 8]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+4
Canonical form of the line equation: 4x-5y+20 = 0
Parametric form of the line equation:
x = 5t
y = 4t+4 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -5
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.1235
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [2.5; 6]
Perpendicular Bisector equation: 5x+4y-36.5 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (5; 8) ; |OB| = 9.434
Scalar product OA .OB = 32
Angle ∠ AOB = 32°19″ = 0.5586 rad