Line slope calculator 3x+7y=28
Straight line given by points A[0; 4] and B[7; 1]
Calculation:
Slope: m = -0.4286Slope-intercept form of line: y = -0.4286x+4
Canonical form of the line equation: 3x+7y-28 = 0
Parametric form of the line equation:
x = 7t
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -23°11'55″ = -0.4049 rad
X intercept: x0 = 9.3333
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.6766
The length of the segment AB: |AB| = 7.6158
Vector: AB = (7; -3)
Normal vector: n = (3; 7)
Midpoint of the segment AB: M = [3.5; 2.5]
Perpendicular Bisector equation: 7x-3y-17 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 4
Angle ∠ AOB = 81°52'12″ = 1.4289 rad