Line slope calculator 3x+8y=32


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.375x+4

Canonical form of the line equation: 3x+8y-32 = 0

Parametric form of the line equation:
x = 8t
y = -3t+4      ; t ∈ R

Slope: m = -0.375

Slope angle of line: φ = -20°33'22″ = -0.3588 rad

X intercept: x0 = 10.6667

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.7453

The length of the segment AB: |AB| = 8.544

Vector: AB = (8; -3)

Normal vector: n = (3; 8)

Midpoint of the segment AB: M = [4; 2.5]

Perpendicular Bisector equation: 8x-3y-24.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 4
Angle ∠ AOB = 82°52'30″ = 1.4464 rad