Line slope calculator 3x+8y=32
Straight line given by points A[0; 4] and B[8; 1]
Calculation:
Slope: m = -0.375Slope-intercept form of line: y = -0.375x+4
Canonical form of the line equation: 3x+8y-32 = 0
Parametric form of the line equation:
x = 8t
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -20°33'22″ = -0.3588 rad
X intercept: x0 = 10.6667
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.7453
The length of the segment AB: |AB| = 8.544
Vector: AB = (8; -3)
Normal vector: n = (3; 8)
Midpoint of the segment AB: M = [4; 2.5]
Perpendicular Bisector equation: 8x-3y-24.5 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 4
Angle ∠ AOB = 82°52'30″ = 1.4464 rad