Line slope calculator x+8y=32
Straight line given by points A[0; 4] and B[8; 3]
Calculation:
Slope: m = -0.125Slope-intercept form of line: y = -0.125x+4
Canonical form of the line equation: x+8y-32 = 0
Parametric form of the line equation:
x = 8t
y = -t+4 ; t ∈ R
Slope angle of line: φ = -7°7'30″ = -0.1244 rad
X intercept: x0 = 32
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.9691
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; -1)
Normal vector: n = (1; 8)
Midpoint of the segment AB: M = [4; 3.5]
Perpendicular Bisector equation: 8x-y-28.5 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 12
Angle ∠ AOB = 69°26'38″ = 1.212 rad