Line slope calculator x+8y=32


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -0.125x+4

Canonical form of the line equation: x+8y-32 = 0

Parametric form of the line equation:
x = 8t
y = -t+4      ; t ∈ R

Slope: m = -0.125

Slope angle of line: φ = -7°7'30″ = -0.1244 rad

X intercept: x0 = 32

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.9691

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; -1)

Normal vector: n = (1; 8)

Midpoint of the segment AB: M = [4; 3.5]

Perpendicular Bisector equation: 8x-y-28.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 12
Angle ∠ AOB = 69°26'38″ = 1.212 rad