Line slope calculator x-8y=-32


Enter coordinates of two different points:

Straight line given by points A[0; 4] and B[8; 5]

Calculation:

Slope-intercept form of line: y = 0.125x+4

Canonical form of the line equation: x-8y+32 = 0

Parametric form of the line equation:
x = 8t
y = t+4      ; t ∈ R

Slope: m = 0.125

Slope angle of line: φ = 7°7'30″ = 0.1244 rad

X intercept: x0 = -32

Y intercept: y0 = q = 4

Distance line from the origin: d0 = 3.9691

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; 1)

Normal vector: n = (1; -8)

Midpoint of the segment AB: M = [4; 4.5]

Perpendicular Bisector equation: 8x+y-36.5 = 0


Vector OA = (0; 4) ;   |OA| = 4
Vector OB = (8; 5) ;   |OB| = 9.434
Scalar product OA .OB = 20
Angle ∠ AOB = 57°59'41″ = 1.0122 rad