Line slope calculator 5x+y=5
Straight line given by points A[0; 5] and B[1; 0]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+5
Canonical form of the line equation: 5x+y-5 = 0
Parametric form of the line equation:
x = t
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 1
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 0.9806
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [0.5; 2.5]
Perpendicular Bisector equation: x-5y+12 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (1; 0) ; |OB| = 1
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad